From nobody@digitalkingdom.org Thu Dec 10 20:41:08 2009 Received: with ECARTIS (v1.0.0; list lojban-beginners); Thu, 10 Dec 2009 20:41:08 -0800 (PST) Received: from nobody by chain.digitalkingdom.org with local (Exim 4.69) (envelope-from ) id 1NIxJT-0006vP-7B for lojban-beginners-real@lojban.org; Thu, 10 Dec 2009 20:41:07 -0800 Received: from mail-iw0-f202.google.com ([209.85.223.202]) by chain.digitalkingdom.org with esmtp (Exim 4.69) (envelope-from ) id 1NIxJN-0006qL-6U for lojban-beginners@lojban.org; Thu, 10 Dec 2009 20:41:04 -0800 Received: by iwn40 with SMTP id 40so202054iwn.28 for ; Thu, 10 Dec 2009 20:40:55 -0800 (PST) DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=gamma; h=domainkey-signature:mime-version:received:in-reply-to:references :date:message-id:subject:from:to:content-type; bh=xaLMLKDTWINLleegEEcwR3shAUTQv+Cw6waXEF6H1aI=; b=lGcktYrV1Zindnc0IdgdJyH3qS9H8vmpGvAJ73BBEIiZUVxwMlUc42hMnlU/HYqdy0 p5mPRTUYMgtgjRbM6Y23TvR7w3wl4HqcJKoNxnlJlHtNGXHW9wc1/ognsuQM23y8bE0r HkkhCXKWuC9BxzPswMKDTS252owsfK40VD/YI= DomainKey-Signature: a=rsa-sha1; c=nofws; d=gmail.com; s=gamma; h=mime-version:in-reply-to:references:date:message-id:subject:from:to :content-type; b=rCOsL0V/cHtb/gcnTmVVBSBWERvP8fsoQtNLq0xzM+fqHudcVObIaNLbQAEefwRN1v s12V4tlbk+JVmARqnz/Am+ANuh5iCiCaoZ1XebeZqW1qyehl7hc+D85FqyuXAbwBzc+d XIxa+NJFIbU2aPNZnUNTC/Vdv4qsAWrYLW90g= MIME-Version: 1.0 Received: by 10.231.146.2 with SMTP id f2mr768885ibv.23.1260506452926; Thu, 10 Dec 2009 20:40:52 -0800 (PST) In-Reply-To: <925d17560912101728q10ed995fg2202bfc242e14b0c@mail.gmail.com> References: <429fde40912101249s24079419g2804c566b311b2a2@mail.gmail.com> <925d17560912101349u1b601d8i299215cf294c57a7@mail.gmail.com> <200912101715.05760.phma@phma.optus.nu> <925d17560912101728q10ed995fg2202bfc242e14b0c@mail.gmail.com> Date: Fri, 11 Dec 2009 15:40:52 +1100 Message-ID: <85c354a20912102040tf3f384asdb76305237a57199@mail.gmail.com> Subject: [lojban-beginners] Re: On units and mekso From: Ross Ogilvie To: lojban-beginners@lojban.org Content-Type: multipart/alternative; boundary=0016e64c06165d200c047a6c87e0 X-archive-position: 2641 X-ecartis-version: Ecartis v1.0.0 Sender: lojban-beginners-bounce@lojban.org Errors-to: lojban-beginners-bounce@lojban.org X-original-sender: oges007@gmail.com Precedence: bulk Reply-to: lojban-beginners@lojban.org X-list: lojban-beginners --0016e64c06165d200c047a6c87e0 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Angular acceleration is in units of inverse square seconds (because radians are dimensionless). e.g. imagine a 3 kg mass on the end of a 5 metre arm, which has an angular acceleration of 0.5 inverse square seconds. The linear force is then 7.5 Newtons. mu'o mi'e ros 2009/12/11 Jorge Llamb=EDas > On Thu, Dec 10, 2009 at 7:15 PM, Pierre Abbat wrote: > > On Thursday 10 December 2009 16:49:57 Jorge Llamb=EDas wrote: > > > >> Only it's actually 3.75 newtons. :) > > > > That depends on whether "2 seconds to the second power" means 2 square > seconds > > or the square of 2 seconds. > > You push a 3 kg object on a frictionless surface for 2 seconds with > both hands, exerting the same constant force with each hand. The > object, which started at rest, moves 5 meters in that time. What is > the force exerted by each hand? The answer is precisely "3 kilograms > times 5 metres divided by 2 seconds to the second power equals 3.75 > newtons". > > In what context would the "2 square seconds" interpretation make > sense? Is the unit "square seconds" ever used for anything? > > > Is "li mo'e lo ki'ogra" the same as "lo ki'ogra"? > > If "li" and "mo'e" are converse converters, I guess they must be. > > mu'o mi'e xorxes > > > > --0016e64c06165d200c047a6c87e0 Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable Angular acceleration is in units of inverse square seconds (because radians= are dimensionless).

e.g. imagine a 3 kg mass on the end of a 5 metr= e arm, which has an angular acceleration of 0.5 inverse square seconds. The= linear force is then 7.5 Newtons.

mu'o mi'e ros

2009/12/11 Jorg= e Llamb=EDas <= jjllambias@gmail.com>
On Thu, Dec 10, 2009 at 7:15 PM, Pierre Abbat <phma@phma.optus.nu> wrote:
> On Thursday 10 December 2009 16:49:57 Jorge Llamb=EDas wrote:
>
>> Only it's actually 3.75 newtons. :) >
> That depends on whether "2 seconds to the second power" mean= s 2 square seconds
> or the square of 2 seconds.

You push a 3 kg object on a frictionless surface for 2 seconds with both hands, exerting the same constant force with each hand. The
object, which started at rest, moves 5 meters in that time. What is
the force exerted by each hand? The answer is precisely "3 kilograms times 5 metres divided by 2 seconds to the second power equals 3.75
newtons".

In what context would the "2 square seconds" interpretation make<= br> sense? Is the unit "square seconds" ever used for anything?

> Is "li mo'e lo ki'ogra" the same as "lo ki'= ogra"?

If "li" and "mo'e" are converse converters, I= guess they must be.

mu'o mi'e xorxes




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