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Date: Mon, 15 Oct 2012 09:02:05 -0700 (PDT)
From: la gleki <gleki.is.my.name@gmail.com>
To: lojban@googlegroups.com
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Subject: Re: [lojban] Can the inconsistency with {seisa'a ... se'u} be overrriden?
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On Monday, October 15, 2012 7:41:29 PM UTC+4, selpa'i wrote:
>
> Am 15.10.2012 17:29, schrieb la gleki:=20
> > the CLL <http://dag.github.com/cll/19/12/>says:=20
> >=20
> > Note: The parser believes that parentheses are attached to the previous=
=20
> > word or construct, because it treats them as syntactic equivalents of=
=20
> > subscripts and other such so-called =E2=80=9Cfree modifiers=E2=80=9D. S=
emantically,=20
> > however, parenthetical remarks are not necessarily attached either to=
=20
> > what precedes them or what follows them.=20
> >=20
> > ...12.8) lu seisa'a la djan. cusku be dei mi klama le zarci=20
> >=20
> >         John said, =E2=80=9CI go to the store=E2=80=9D.=20
> >=20
> > 12.9)   lu mi klama seisa'a la djan cusku le zarci=20
> >         =E2=80=9CI go=E2=80=9D, John said, =E2=80=9Cto the store=E2=80=
=9D.=20
> >=20
> >=20
> >=20
> > So is there any method of attaching sei ... se'u to bridi or jufra, not=
=20
> > to the previous word?=20
>
> SEI doesn't attach to the previous word semantically. It works just like=
=20
> COI in that regard. The quote above from the CLL says the same. It's a=20
> free modifier that floats around in the bridi.=20
>

Does it mean then that=20

*do sei mi prami do se'u klama la .landyn.*
and=20
*do klama la .landyn. sei mi prami do se'u*

mean the same?



> mu'o mi'e la selpa'i=20
> --=20
> pilno zo le xu .i lo dei bangu cu se cmene zo lojbo .e nai zo lejbo=20
>
> do=E1=BB=8B m=C3=A8lbi mlen=C3=AC'u=20
>     .i do c=C3=A0tlu ki'u=20
> ma fe la x=C3=A0mpre =C5=ADu=20
>     .i do t=C3=ACnsa c=C3=A0rmi=20
> gi'e s=C3=ACrji se t=C3=A0rmi=20
>     .i ta=E1=BB=8B bo pu c=C3=ACtka lo gr=C3=A0na ku=20
>
>
> .=20
>

--=20
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<br><br>On Monday, October 15, 2012 7:41:29 PM UTC+4, selpa'i wrote:<blockq=
uote class=3D"gmail_quote" style=3D"margin: 0;margin-left: 0.8ex;border-lef=
t: 1px #ccc solid;padding-left: 1ex;">Am 15.10.2012 17:29, schrieb la gleki=
:
<br>&gt; the CLL &lt;<a href=3D"http://dag.github.com/cll/19/12/" target=3D=
"_blank">http://dag.github.com/cll/19/<wbr>12/</a>&gt;says:
<br>&gt;
<br>&gt; Note: The parser believes that parentheses are attached to the pre=
vious
<br>&gt; word or construct, because it treats them as syntactic equivalents=
 of
<br>&gt; subscripts and other such so-called =E2=80=9Cfree modifiers=E2=80=
=9D. Semantically,
<br>&gt; however, parenthetical remarks are not necessarily attached either=
 to
<br>&gt; what precedes them or what follows them.
<br>&gt;
<br>&gt; ...12.8) lu seisa'a la djan. cusku be dei mi klama le zarci
<br>&gt;
<br>&gt; &nbsp; &nbsp; &nbsp; &nbsp; John said, =E2=80=9CI go to the store=
=E2=80=9D.
<br>&gt;
<br>&gt; 12.9) &nbsp; lu mi klama seisa'a la djan cusku le zarci
<br>&gt; &nbsp; &nbsp; &nbsp; &nbsp; =E2=80=9CI go=E2=80=9D, John said, =E2=
=80=9Cto the store=E2=80=9D.
<br>&gt;
<br>&gt;
<br>&gt;
<br>&gt; So is there any method of attaching sei ... se'u to bridi or jufra=
, not
<br>&gt; to the previous word?
<br>
<br>SEI doesn't attach to the previous word semantically. It works just lik=
e=20
<br>COI in that regard. The quote above from the CLL says the same. It's a=
=20
<br>free modifier that floats around in the bridi.
<br></blockquote><div><br></div><div>Does it mean then that&nbsp;</div><div=
><br></div><div><i>do sei mi prami do se'u klama la .landyn.</i></div><div>=
<div>and&nbsp;</div><div><i>do klama la .landyn.&nbsp;sei mi prami do se'u<=
/i></div></div><div><br></div><div>mean the same?</div><div><br></div><div>=
<br></div><blockquote class=3D"gmail_quote" style=3D"margin: 0;margin-left:=
 0.8ex;border-left: 1px #ccc solid;padding-left: 1ex;">
<br>mu'o mi'e la selpa'i
<br>--=20
<br>pilno zo le xu .i lo dei bangu cu se cmene zo lojbo .e nai zo lejbo
<br>
<br>do=E1=BB=8B m=C3=A8lbi mlen=C3=AC'u
<br>&nbsp; &nbsp; .i do c=C3=A0tlu ki'u
<br>ma fe la x=C3=A0mpre =C5=ADu
<br>&nbsp; &nbsp; .i do t=C3=ACnsa c=C3=A0rmi
<br>gi'e s=C3=ACrji se t=C3=A0rmi
<br>&nbsp; &nbsp; .i ta=E1=BB=8B bo pu c=C3=ACtka lo gr=C3=A0na ku
<br>
<br>
<br>.
<br></blockquote>

<p></p>

-- <br />
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