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Date: Sun, 9 Jun 2013 17:58:47 -0300
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Subject: Re: [lojban] cmevla as a class of brivla
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On Sun, Jun 9, 2013 at 5:20 PM, John E Clifford <kali9putra@yahoo.com>wrote:

> The name-others distinction in logic is  not about function (although
> that, too) but about form. Could Lojban names look just like other
> expressions?  They don't, but that is not the issue.
>

Some do, some don't.


> What kind of a predicate is {djan zei pol}? It is said to have lujvo glue,
> but does not appear to be any sort of lujvo (not that I can remember all
> nine-and-ninety rules for lujvo, but they all seemed to end up with
> something with an early CC and a final vowel).
>

"zei" joins (almost) any two words into a predicate. (There are a few
exceptional words, "zei" itself being one of them, that's why it's "almost"
any two words.)


> Two things.  I suspect that we have different understandings from the
> volumes on the topic of the nature and power of dotside.
>

I suspect so too. All dotside does is allow cmevla to contain the syllables
doi/la/lai/la'i, at the price of requiring a dot at the beginning of every
cmevla. You seem to think it's something much more powerful.


> So I would allow compound names, just have the total demarcated.
>

Demarcated how? ".djan. .smit." can't be both one compound name consisting
of two cmevla, and also two sumti. If you allowed compound names it
couldn't be two sumti.

mu'o mi'e xorxes

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<div dir=3D"ltr"><br><div class=3D"gmail_extra"><div class=3D"gmail_quote">=
On Sun, Jun 9, 2013 at 5:20 PM, John E Clifford <span dir=3D"ltr">&lt;<a hr=
ef=3D"mailto:kali9putra@yahoo.com" target=3D"_blank">kali9putra@yahoo.com</=
a>&gt;</span> wrote:<br>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex"><div><div style=3D"font-size:12pt;font-famil=
y:times new roman,new york,times,serif">The name-others distinction in logi=
c is=A0 not about function (although that, too) but about form. Could Lojba=
n names look just like other expressions?=A0 They don&#39;t, but that is no=
t the issue.<br>
</div></div></blockquote><div><br></div><div style>Some do, some don&#39;t.=
</div><div style><br></div><div>=A0</div><blockquote class=3D"gmail_quote" =
style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><di=
v>
<div style=3D"font-size:12pt;font-family:times new roman,new york,times,ser=
if">What kind of a predicate is {djan zei pol}? It is said to have lujvo gl=
ue, but does not appear to be any sort of lujvo (not that I can remember al=
l nine-and-ninety rules for lujvo, but they all seemed to end up with somet=
hing with an early CC and a final vowel).=A0</div>
</div></blockquote><div><br></div><div style>&quot;zei&quot; joins (almost)=
 any two words into a predicate. (There are a few exceptional words, &quot;=
zei&quot; itself being one of them, that&#39;s why it&#39;s &quot;almost&qu=
ot; any two words.)</div>
<div><br></div><div>=A0</div><blockquote class=3D"gmail_quote" style=3D"mar=
gin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div><div style=
=3D"font-size:12pt;font-family:times new roman,new york,times,serif">Two th=
ings.=A0 I suspect that we have different understandings from the volumes o=
n the topic of the nature and power of dotside.=A0</div>
</div></blockquote><div><br></div><div style>I suspect so too. All dotside =
does is allow cmevla to contain the syllables doi/la/lai/la&#39;i, at the p=
rice of requiring a dot at the beginning of every cmevla. You seem to think=
 it&#39;s something much more powerful.</div>
<div><br></div><div>=A0</div><blockquote class=3D"gmail_quote" style=3D"mar=
gin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><div><div style=
=3D"font-size:12pt;font-family:times new roman,new york,times,serif"> So I =
would allow compound names, just have the total demarcated.=A0 </div>
</div></blockquote><div><br></div><div style>Demarcated how? &quot;.djan. .=
smit.&quot; can&#39;t be both one compound name consisting of two cmevla, a=
nd also two sumti. If you allowed compound names it couldn&#39;t be two sum=
ti.</div>
<div><br></div><div style>mu&#39;o mi&#39;e xorxes</div><div style><br></di=
v></div></div></div>

<p></p>

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