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[2607:f8b0:400d:c04::232]) by gmr-mx.google.com with ESMTPS id lu6si1992751qcb.3.2014.10.26.08.39.31 for (version=TLSv1 cipher=ECDHE-RSA-RC4-SHA bits=128/128); Sun, 26 Oct 2014 08:39:31 -0700 (PDT) Received-SPF: pass (google.com: domain of lytlesw@gmail.com designates 2607:f8b0:400d:c04::232 as permitted sender) client-ip=2607:f8b0:400d:c04::232; Received: by mail-qg0-f50.google.com with SMTP id a108so315748qge.37 for ; Sun, 26 Oct 2014 08:39:31 -0700 (PDT) X-Received: by 10.224.130.71 with SMTP id r7mr1338499qas.69.1414337971474; Sun, 26 Oct 2014 08:39:31 -0700 (PDT) MIME-Version: 1.0 Received: by 10.229.84.199 with HTTP; Sun, 26 Oct 2014 08:39:01 -0700 (PDT) In-Reply-To: <544CFB57.90908@gmail.com> References: <5bf2774f-1cad-4603-8fa5-d4d96f3f3fed@googlegroups.com> <544B9F7B.4040007@gmail.com> <544CFB57.90908@gmail.com> From: MorphemeAddict Date: Sun, 26 Oct 2014 11:39:01 -0400 Message-ID: Subject: =?UTF-8?B?UmU6IFtsb2piYW5dIERvZXMgTG9qYmFuIGhhdmUgYW4gZXF1aXZhbGVudCBvZiDokKwv?= =?UTF-8?B?66eML+S4hyAoMTAgdGhvdXNhbmQpPw==?= To: lojban@googlegroups.com X-Original-Sender: lytlesw@gmail.com X-Original-Authentication-Results: gmr-mx.google.com; spf=pass (google.com: domain of lytlesw@gmail.com designates 2607:f8b0:400d:c04::232 as permitted sender) smtp.mail=lytlesw@gmail.com; dkim=pass header.i=@gmail.com; dmarc=pass (p=NONE dis=NONE) header.from=gmail.com Reply-To: lojban@googlegroups.com Precedence: list Mailing-list: list lojban@googlegroups.com; contact lojban+owners@googlegroups.com List-ID: X-Google-Group-Id: 1004133512417 List-Post: , List-Help: , List-Archive: , List-Unsubscribe: , Content-Type: multipart/alternative; boundary=001a1132eb2861d69605065538a0 X-Spam-Score: -1.9 (-) X-Spam_score: -1.9 X-Spam_score_int: -18 X-Spam_bar: - --001a1132eb2861d69605065538a0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: quoted-printable You're asking me to figure it out on my own, and I already tried that. stevo On Sun, Oct 26, 2014 at 9:47 AM, Ilmen wrote: > > On 26/10/2014 06:29, MorphemeAddict wrote: > > How does {pa se gei vo} mean (1=C3=9710^4, scientific notation)? > My listing gives the definition of {gei} as 'exponential order of > magnitude/value/base; [b * (c to the a power)]'. > Using {gei} and 1=C3=9710^4, a=3D4, b=3D1, c=3D10. How does "se" rearrang= e the parts > of {gei}? > > stevo > > > You can find an example of SE+VUhU at CLL Chapter 18 Verse 21.1 > . > > =E2=80=9Cse=E2=80=9D can be used to convert an operator as if it were a= selbri, so that > its arguments are exchanged. For example: > > 21.1) li ci se vu'u vo du li pa > The-number three (inverse) minus four equals the-number one. > 3 subtracted from 4 equals 1. > > > mi'e la .ilmen. mu'o > > -- > You received this message because you are subscribed to the Google Groups > "lojban" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to lojban+unsubscribe@googlegroups.com. > To post to this group, send email to lojban@googlegroups.com. > Visit this group at http://groups.google.com/group/lojban. > For more options, visit https://groups.google.com/d/optout. > --=20 You received this message because you are subscribed to the Google Groups "= lojban" group. To unsubscribe from this group and stop receiving emails from it, send an e= mail to lojban+unsubscribe@googlegroups.com. To post to this group, send email to lojban@googlegroups.com. Visit this group at http://groups.google.com/group/lojban. For more options, visit https://groups.google.com/d/optout. --001a1132eb2861d69605065538a0 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable
You're asking me to figure it out on my own, and I alrea= dy tried that.=C2=A0

stevo

On Sun, Oct 26, 2014 at 9:47 AM, Ilmen <ilmen.pokebip@gmail.com> wrote:
=20 =20 =20

On 26/10/2014 06:29, MorphemeAddict wrote:
How does=C2=A0{pa se gei vo} mean (1=C3=9710^4, scientific notation)?=C2=A0
My listing gives the definition of {gei} as 'exponential order of magnitude/value/base; [b * (c to the a power)]'.=C2=A0
Using {gei} and=C2=A01=C3=9710^4, a=3D4, b=3D1, c=3D10. How does "se" rearrange the parts of {gei}?=C2=A0

stevo

You can find an example of SE+VUhU at CLL Chapter 18 Verse 21.1.

=E2=80=9Cse=E2=80=9D can be used to convert an operator as i= f it were a selbri, so that its arguments are exchanged. For example:

21.1)  li ci se vu'=
;u vo du li pa
       The-number three (inverse) minus four equals the-number one.
       3 subtracted from 4 equals 1.

mi'e la .ilmen. mu'o

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