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[2a00:1450:4010:c07::22d]) by gmr-mx.google.com with ESMTPS id f7si465923lbf.0.2016.04.09.03.52.22 for (version=TLS1_2 cipher=ECDHE-RSA-AES128-GCM-SHA256 bits=128/128); Sat, 09 Apr 2016 03:52:22 -0700 (PDT) Received-SPF: pass (google.com: domain of ciuak.prog@gmail.com designates 2a00:1450:4010:c07::22d as permitted sender) client-ip=2a00:1450:4010:c07::22d; Received: by mail-lf0-x22d.google.com with SMTP id g184so104706073lfb.3 for ; Sat, 09 Apr 2016 03:52:22 -0700 (PDT) MIME-Version: 1.0 X-Received: by 10.25.37.135 with SMTP id l129mr5677164lfl.56.1460199142568; Sat, 09 Apr 2016 03:52:22 -0700 (PDT) Received: by 10.112.105.168 with HTTP; Sat, 9 Apr 2016 03:52:22 -0700 (PDT) Date: Sat, 9 Apr 2016 11:52:22 +0100 Message-ID: Subject: =?UTF-8?B?W2xvamJhbl0gwqtzZSBnb2nCuw==?= From: Bruno Panasiewicz To: lojban@googlegroups.com Content-Type: multipart/alternative; boundary=001a11472aee31b9af05300b1b2e X-Original-Sender: ciuak.prog@gmail.com X-Original-Authentication-Results: gmr-mx.google.com; dkim=pass header.i=@gmail.com; spf=pass (google.com: domain of ciuak.prog@gmail.com designates 2a00:1450:4010:c07::22d as permitted sender) smtp.mailfrom=ciuak.prog@gmail.com; dmarc=pass (p=NONE dis=NONE) header.from=gmail.com Reply-To: lojban@googlegroups.com Precedence: list Mailing-list: list lojban@googlegroups.com; contact lojban+owners@googlegroups.com List-ID: X-Spam-Checked-In-Group: lojban@googlegroups.com X-Google-Group-Id: 1004133512417 List-Post: , List-Help: , List-Archive: , List-Unsubscribe: , X-Spam-Score: -1.8 (-) X-Spam_score: -1.8 X-Spam_score_int: -17 X-Spam_bar: - --001a11472aee31b9af05300b1b2e Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: quoted-printable coi ro do The problem with =C2=ABgoi=C2=BB is that it is ambiguous=E2=80=94one can no= t know which way the assignment goes. I was thinking about a nice solution, and found one. Basically, =C2=ABgoi= =C2=BB assigns the left sumti to the right one. If one wants to do it the other way around, he says =C2=ABse goi=C2=BB. For example: - *ko'a goi ko'e* =E2=80=93 it-1, from now on referred to as it-2; - *la .alis. se goi ti* =E2=80=93 Alice, which from now on refers to thi= s thing here. Actually, this syntax can work with any other GOI! I will throw more examples at you: - *lo vi ninmu se po lo junla* =E2=80=93 this woman here owning a watch = (=C2=ABpo=C2=BB: owned by..., =C2=ABse po=C2=BB: owning...); - lo vi nanmu se po'e lo panzi =E2=80=93 this man here having a child (= =C2=ABpo'e=C2=BB: intrinsic property of..., =C2=ABse po'e=C2=BB: owning intrinsically...). What do you think? mi'e la .uakci mu'o zo =C2=ABcrocatra=C2=BB zo'o --=20 You received this message because you are subscribed to the Google Groups "= lojban" group. To unsubscribe from this group and stop receiving emails from it, send an e= mail to lojban+unsubscribe@googlegroups.com. To post to this group, send email to lojban@googlegroups.com. Visit this group at https://groups.google.com/group/lojban. For more options, visit https://groups.google.com/d/optout. --001a11472aee31b9af05300b1b2e Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable
coi ro do
The problem with =C2=ABgoi=C2=BB is that it is ambiguous=E2= =80=94one can not know which way the assignment goes.
I = was thinking about a nice solution, and found one. Basically, =C2=ABgoi=C2= =BB assigns the left sumti to the right one. If one wants to do it the othe= r way around, he says =C2=ABse goi=C2=BB. For example:
  • ko'a goi ko'e =E2=80=93 it-1, from now on = referred to as it-2;
  • la .alis. se goi ti =E2=80=93 Alice, which from now on ref= ers to this thing here.
Actually, this syntax can work with any other GOI! I will throw more exa= mples at you:
  • <= font face=3D"times new roman, serif">lo vi ninmu se po lo junla =E2= =80=93 this woman here owning a watch (=C2=ABpo=C2=BB: owned by..., =C2=ABs= e po=C2=BB: owning...);
  • What do you think?
<= font face=3D"times new roman, serif" color=3D"#999999">mi'e la .uakci m= u'o
zo =C2=ABcrocatra=C2=BB zo'o

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