Return-Path: <@FINHUTC.HUT.FI:LOJBAN@CUVMB.BITNET> Received: from FINHUTC.hut.fi by xiron.pc.helsinki.fi with smtp (Linux Smail3.1.28.1 #1) id m0r6MJ1-00005bC; Sat, 12 Nov 94 19:32 EET Message-Id: Received: from FINHUTC.HUT.FI by FINHUTC.hut.fi (IBM VM SMTP V2R2) with BSMTP id 7053; Sat, 12 Nov 94 19:32:16 EET Received: from SEARN.SUNET.SE (NJE origin MAILER@SEARN) by FINHUTC.HUT.FI (LMail V1.1d/1.7f) with BSMTP id 7047; Sat, 12 Nov 1994 19:32:15 +0200 Received: from SEARN.SUNET.SE (NJE origin LISTSERV@SEARN) by SEARN.SUNET.SE (LMail V1.2a/1.8a) with BSMTP id 9336; Sat, 12 Nov 1994 18:29:05 +0100 Date: Sat, 12 Nov 1994 12:34:13 EST Reply-To: jorge@PHYAST.PITT.EDU Sender: Lojban list From: Jorge Llambias Subject: Re: Re Cowan#2 lo, da poi X-To: lojban@cuvmb.cc.columbia.edu To: Veijo Vilva Content-Length: 1387 Lines: 41 la djer cusku di'e > There might be other contexts besides negation where "da poi" as a > direct substitution for "lo" would yield unexpected results. > For example: > > 1). lo ro tanxe cu ckaji lo xa sefta > All the real boxes have the property of six surfaces. (The boxes exist) No, {ro} here is an inside quantifier. It says: "At least one of all real boxes has the property of at least one of the six real surfaces there are." In the property place you need a {le ka}, and for "all boxes", you need an outside quantifier. ro lo tanxe cu ckaji le ka se sefta xa da Every box has the property of having as surfaces exactly six things. > 2). da poi ro tanxe cu ckaji lo xa sefta > Something which is all boxes has the propery of six surfaces. {da poi ro tanxe} is not grammatical. {lo broda} is {su'o lo ro broda} and is equivalent to {da poi broda}, so you have to replace {lo ro tanxe}={lo tanxe} by {da poi broda}. {ro lo tanxe} would be equivalent to {ro da poi tanxe}. "Something which is all boxes" could be {da poi tanxe romei}. > If my reasoning is correct here, and I almost wish it is not, I hope > that someone will find a quick fix, and that harmony will prevail in > lo land. Your reasoning is not correct because you are mixing outside quantifiers (true quantifiers) and inside quantifiers (cardinality markers, or whatever they are called). Jorge