From pycyn@aol.com Sun Jun 10 18:15:03 2001 Return-Path: X-Sender: Pycyn@aol.com X-Apparently-To: lojban@yahoogroups.com Received: (EGP: mail-7_1_3); 11 Jun 2001 01:15:03 -0000 Received: (qmail 37918 invoked from network); 11 Jun 2001 01:15:03 -0000 Received: from unknown (10.1.10.27) by l8.egroups.com with QMQP; 11 Jun 2001 01:15:03 -0000 Received: from unknown (HELO imo-d10.mx.aol.com) (205.188.157.42) by mta2 with SMTP; 11 Jun 2001 01:15:03 -0000 Received: from Pycyn@aol.com by imo-d10.mx.aol.com (mail_out_v30.22.) id r.cc.16391f4f (4256) for ; Sun, 10 Jun 2001 21:14:55 -0400 (EDT) Message-ID: Date: Sun, 10 Jun 2001 21:14:55 EDT Subject: RE: zi'o and modals To: lojban@yahoogroups.com MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="part1_cc.16391f4f.2855758f_boundary" X-Mailer: AOL 6.0 for Windows US sub 10519 From: pycyn@aol.com X-Yahoo-Message-Num: 7771 --part1_cc.16391f4f.2855758f_boundary Content-Type: text/plain; charset="ISO-8859-1" Content-Transfer-Encoding: quoted-printable In a message dated 6/10/2001 5:53:33 PM Central Daylight Time,=20 jay.kominek@colorado.edu writes: > : mi klama =A0=A0=A0=A0=A0; I go > > b: go'i bai ma =A0=A0; Compelled by what? > > a: zi'o =A0=A0=A0=A0=A0=A0=A0=A0=A0; Nonexistent, doesn't apply > > b: je'e =A0=A0=A0=A0=A0=A0=A0=A0=A0; roger. >=20 > Shouldn't a respond with noda, not zi'o? >=20 Yes, for the most part. =A0The whole idea of modal+{zi'o} is kinda odd, sin= ce=20 {zi'o} is there to incapacitate an essential part of a relation. =A0So why = add=20 a new factor and then cut it off? =A0The {zi'o} answer above might make tha= t=20 point over and above {noda}. --part1_cc.16391f4f.2855758f_boundary Content-Type: text/html; charset="ISO-8859-1" Content-Transfer-Encoding: quoted-printable In a message dated 6/10/2001 5:53:33 PM Central Daylight Time,=20
jay.kominek@colorado.edu writes:



: mi klama =A0=A0=A0=A0= =A0; I go
> b: go'i bai ma =A0=A0; Compelled by what?
> a: zi'o =A0=A0=A0=A0=A0=A0=A0=A0=A0; Nonexistent, doesn't apply
> b: je'e =A0=A0=A0=A0=A0=A0=A0=A0=A0; roger.

Shouldn't a respond with noda, not zi'o?




Yes, for the most part. =A0The whole idea of modal+{zi'o} is kinda odd,= since=20
{zi'o} is there to incapacitate an essential part of a relation. =A0So = why add=20
a new factor and then cut it off? =A0The {zi'o} answer above might make= that=20
point over and above {noda}. --part1_cc.16391f4f.2855758f_boundary--