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and the result was:13.

I noticed that it "stops" parsing with the first character that doesn't belong to the numeral system specified in the 2nd argument, so callingparseInt('fg',16)I would get15as a result.

In my opinion, it should return NaN. Can anyone explain to me why it doesn't? Why would anyone want this function to behave like this (return an integer even if it isn't the precise representation of the string passed) ?

Since JS is dynamically typed, some strings work just fine as numbers without any work on your part. For instance:

 "21" / 3;   // => 7  "12.4" / 4; // => 3.1

No need forparseIntthere, because"21"and"12.4"are essentially numbers already. If, however the string was"12.4xyz"then you would indeed getNaNwhen dividing, since that is decidedly not a number and can't be implicitly cast or coerced to one.

You can also explicitly "cast" a string to number withNumber(someString).While it too only supports base 10,it will indeed returnNaNfor invalid strings.