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Subject: Re: [lojban-beginners] Question about {roda}
From: ".arpis." <rpglover64+jbobau@gmail.com>
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Conversation I had with Lindar off the list, reposted at his request:

Lindar:
Unless I'm vastly mistaken, (ro prenu) and (ro lo prenu) are identical in
meaning. Assuming this, I would like to point out that it does not talk
about an inner quantifier, which means that we are speaking of all people
out of an implicit number.

(If you'd like to repost any of this to the list, feel free. I can't access
g-groups for the next few days.)

Me:
http://dag.github.com/cll/16/6/ and the fourth point under "lo" on
http://www.lojban.org/tiki/How+to+use+xorlo
seem to state the following:
{ro broda} is equivalent to {ro da poi broda}
{ro lo broda} is equivalent to {ro broda}

It seems (to me, who is not well versed in lojban's quantifier semantics)
that {lo}'s default inner quantifier is still {ro}, and this only changes if
there are no quantifiers present at all.

Lindar:
The CLL is wrong (doesn't include xorlo) and the xorlo article contradicts
itself. In the very same section it says lo has no default quantifier.

Me:
I still don't quite understand it (I looked at
http://www.lojban.org/tiki/BPFK+Section%3A+gadri), but I have convinced
myself that {ro broda} refers to all of some unspecified number of {broda}.

I think this means that I agree with your latest statement to the list.

Lindar:
Yes, that is my assertation. I wish I had access to a machine that would let
me on the list. Repost this conversation for me?

-- 
mu'o mi'e .arpis.

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Conversation I had with Lindar off the list, reposted at his request:<br><b=
r>Lindar:<br>Unless I&#39;m vastly mistaken, (ro prenu) and (ro lo prenu) a=
re identical in meaning. Assuming this, I would like to point out that it d=
oes not talk about an inner quantifier, which means that we are speaking of=
 all people out of an implicit number.<br>
<br>(If you&#39;d like to repost any of this to the list, feel free. I can&=
#39;t access g-groups for the next few days.)<br><br>Me:<br><a href=3D"http=
://dag.github.com/cll/16/6/">http://dag.github.com/cll/16/6/</a> and the fo=
urth point under &quot;lo&quot; on <a href=3D"http://www.lojban.org/tiki/Ho=
w+to+use+xorlo">http://www.lojban.org/tiki/How+to+use+xorlo</a><br>
seem to state the following:<br>{ro broda} is equivalent to {ro da poi brod=
a}<br>{ro lo broda} is equivalent to {ro broda}<br><br>It seems (to me, who=
 is not well versed in lojban&#39;s quantifier semantics) that {lo}&#39;s d=
efault inner quantifier is still {ro}, and this only changes if there are n=
o quantifiers present at all.<br>
<br>Lindar:<br>The CLL is wrong (doesn&#39;t include xorlo) and the xorlo a=
rticle contradicts itself. In the very same section it says lo has no defau=
lt quantifier.<br><br>Me:<br>I still don&#39;t quite understand it (I looke=
d at <a href=3D"http://www.lojban.org/tiki/BPFK+Section%3A+gadri">http://ww=
w.lojban.org/tiki/BPFK+Section%3A+gadri</a>), but I have convinced myself t=
hat {ro broda} refers to all of some unspecified number of {broda}.<br>
<br>I think this means that I agree with your latest statement to the list.=
<br><br>Lindar:<br>Yes, that is my assertation. I wish I had access to a ma=
chine that would let me on the list. Repost this conversation for me?<br>
<br>-- <br>mu&#39;o mi&#39;e .arpis.<br><br>

<p></p>

-- <br />
You received this message because you are subscribed to the Google Groups "=
Lojban Beginners" group.<br />
To post to this group, send email to lojban-beginners@googlegroups.com.<br =
/>
To unsubscribe from this group, send email to lojban-beginners+unsubscribe@=
googlegroups.com.<br />

For more options, visit this group at http://groups.google.com/group/lojban=
-beginners?hl=3Den.<br />



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