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Date: Thu, 24 Feb 2011 15:08:41 -0800 (PST)
From: Lindar <lindarthebard@yahoo.com>
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Subject: Re: [lojban-beginners] Question about {roda}
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Yes, I'm finally on for a little bit. My assertion is that {ro broda} is 
-not- equivalent to {ro da poi broda} because {ro da} is explicitly 
EVERYTHING. {lo} does not have any default quantifiers under xorlo, which 
means that while {roda poi broda} is literally everything that brodas, {ro 
lo broda} or {ro broda} is all of an implicit number of brodas. {ro da poi 
broda} is equal to {ro lo ro broda} AFAIK.

Am I wrong on any point? Cos the xorlo article contradicts itself, and the 
CLL doesn't feature xorlo-related content.

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Yes, I'm finally on for a little bit. My assertion is that {ro broda} is -n=
ot- equivalent to {ro da poi broda} because {ro da} is explicitly EVERYTHIN=
G. {lo} does not have any default quantifiers under xorlo, which means that=
 while {roda poi broda} is literally everything that brodas, {ro lo broda} =
or {ro broda} is all of an implicit number of brodas. {ro da poi broda} is =
equal to {ro lo ro broda} AFAIK.<div><br></div><div>Am I wrong on any point=
? Cos the xorlo article contradicts itself, and the CLL doesn't feature xor=
lo-related content.</div>

<p></p>

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