> > --=20 You received this message because you are subscribed to the Google Groups "= Lojban Beginners" group. To view this discussion on the web visit https://groups.google.com/d/msg/lo= jban-beginners/-/U_CQyzqFZUUJ. To post to this group, send email to lojban-beginners@googlegroups.com. To unsubscribe from this group, send email to lojban-beginners+unsubscribe@= googlegroups.com. For more options, visit this group at http://groups.google.com/group/lojban= -beginners?hl=3Den. ------=_Part_1506_30948943.1320768880662 Content-Type: text/html; charset=ISO-8859-1 Content-Transfer-Encoding: quoted-printable This makes things even more strange.

Now tell me what is the difference= between

"lo mi gerku cu xamgu" and "lo me mi gerku cu xamgu" ?The first one is translated as
"lo any/some mi gerku dog(s) [of] I, me= )2 cu is/does =AB3xamgu being good=BB3]1"

and the second one as"lo any/some (3me amongst those that are mi I, me [type-of] gerku dog(s))= 3)2 cu is/does =AB4xamgu being good=BB4]1"

Yes, "lo mi gerku" meanin= g "my dog" is quite handy, but why it breaks the logic of anything learnt b= efore ?

mi gerku means "I'm a dog" and when it is used as a sumti= in the phrase

i= t must mean <"I'm a dog" is good> whatever that means.

"me mi gerku" (my dog) has much more sense as it clear resembles= "prenu gerku" (person's dog).

I feel that the "ru= le" of transforming "I am" into "mine" when adding "lo" is absolutely alien= to other lojbanic rules.

On Thursday, August 4, 2011 6:10:49= PM UTC+4, Kevin Reid wrote:
On Aug 4, 2011, at 6:47, najrut wrote:

> But ... is it an= yway possible to form tanru with pro-sumti included ?
It is possible = as Jorge Llamb=EDas explained, with "me <sumti>" which is a conversio= n to the selbri "x1 is <sumti>".
dei = ; me mi notci
This [is a] Kevinish message. &= nbsp;
--
Kevin Reid &nb= sp; &l= t;http://switchb.o= rg/kpreid/>

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You received this message because you are subscribed to the Google Groups "= Lojban Beginners" group.
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=20 To post to this group, send email to lojban-beginners@googlegroups.com.
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