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[lojban-beginners] Re: logical proofs?
--- Robin Lee Powell wrote:
> > > > Suppose that we have a finite list of prime numbers.
> > > .i sruma lo du'u mi'o ponse lo liste be me'i ci'i broda
> >
> > I like {me'i ci'i} for finite, but {ponse}? In what sense do we own
> > the list? I'd just say: {ru'a fo'a liste me'i ci'i broda}
>
> Forgot ru'a, thanks. What is it with you and fo'a?
I hardly use it. In this case, I was going to use ko'a, but then
I noticed you later use ko'a for something else, so I used fo'a to
avoid confusion.
> > > > This number is, by a previous result (you could prove it if you
> > > > wanted), guaranteed to be divisible by some prime number - perhaps
> > > > itself.
> > > .i ko'a to se nibli lo pu nu jarco toi cu kakne lo nu fendi fi pa
> > > broda goi ko'e to cumki lo nu du ko'a toi
> > i ko'a sei lo pu nu jarco cu nibli cu mulpi'i su'o broda goi ko'e no'u
> > ju'o cu'i ko'a
>
> I'm not as comfortable with sei as you.
>
> That's a very iffy use of ju'o cu'i; I'm not at all sure that ju'o cu'i
> is strong enough to eliminate the identicality of no'u.
It isn't meant to eliminate the identicality, it just flags it
as a possibility. I'm not sure ju'ocu'i is the best choice here,
but cumki doesn't seem right to me.
> > mulpi'i: x1 pilji x2 x3 ije x1 e x2 e x3 mulnau
>
> You mean mulna'u there, yes?
Yes, sorry.
> Why not just use pilji?
Because we only want integer factors.
> > i.e. "x1 is divisible by x2"
>
> To me, "divisible" is more like fendi, but fair enough.
fendi has an agent, it has little to do with numbers. Division
of numbers is dilcu.
> [prime definition]
> > > da poi mulna'usle cei broda cu ma'u zei mulna'u gi'e mulna'u pilji
> > > po'o pa da
> >
> > Only "1" is mulna'u pilji pa da, all other primes have exactly two
> > natural divisors.
>
> Sorry, I meant "pa boi da".
{pa boi da} is the same as {pa da}. Did you mean {li pa da}?
But every number, not just primes are pilji li pa da.
mu'o mi'e xorxes
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