<<
Why is the x2 of jmina the thing added to, but the x3 of vimcu is the
thing subtracted from?
>>
'Tain't. That is, this is the wrong question. The right one is "Why is the second definition of {jmina} backwards of the first: "x1 adds x2 to x3 with result x4" but then
"x1 augments x2 by x3", when it should be (as {vimcu} and the first definiton show) "x1 augments x3 by x2"?
| Yahoo! Groups Sponsor | |||
|
|||
To unsubscribe, send mail to lojban-unsubscribe@onelist.com
Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service.