RE: [lojban] Re: grammar oddity challenge

["Craig" <ragnarok@pobox.com>]

>> >> On Tue, Mar 23, 2004 at 02:00:04PM -0800, Jorge Llamb?as wrote:
>> >
>> >The answer I had in mind was any brivla of
>> >the form {zei zei <any-word>}.
>>
>> Is that even a brivla? Because, technically, it doesn't valsi.

>If it is, it is indeed a boundary case.

>It is a brivla at least in parser terms:
>"a. Token sequences of the form any - (ZEI - any) ..., where
>there may be any number of ZEIs, are merged into a single token
>of selma'o BRIVLA."

But selma'o BRIVLA only exists in the mind of the parser. It certainly isn't
a real group of cmavo - in fact, the terms "brivla" and "cmavo" are mutually
exclusive, IIRC.

 - mi'e .kreig.daniyl.

ragnarok@pobox.com
teucer@bnomic.org



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