Re: [lojban] racli/ralci

[Jorge Llambías <jjllambias@gmail.com>]

On Thu, Aug 2, 2012 at 6:10 AM, Ian Johnson <blindbravado@gmail.com> wrote:
> On Wed, Aug 1, 2012 at 9:38 PM, Jorge Llambías <jjllambias@gmail.com> wrote:
>>
>> I don't think so. "blanu" for example will block "planu", but it won't
>> block "plana", so by playing with the final vowel you can probably
>> accomodate all 20315 four-letter initial forms.
>
> I see what you mean. It would be interesting to attempt this
> computationally; the "transitivity" if you will of the blocking rules makes
> this seem like it could be subtler than either of us are seeing. You're
> closer to right than I was, though, if not actually right.

But the blocking rules are for the most part not transitive. if b
blocks p and p blocks f, it doesn't follow that b blocks f. The only
transitive group is k/x/g. If I'm not mistaken, you can mostly do it
with only two vowels. You only need 3 vowels when k/g/x are involved.
The blocking rules sort all the forms in groups of up to 32 members.
For example, you can sort the blanu group (16 members) with only two
vowels as follows:

blanu bramu plamu pranu flanu framu vlamu vranu
plana prama blama brana vlana vrama flama frana

For the kakne group (18 members) you need three vowels:

kakne kagme xaxme xagne gakme gaxne
kagni kaxmi xakmi xaxni gakni gagmi
kakma kaxna xakna xagma gaxma gagna

The most numerous groups contain 32 members, but can be sorted with
only two vowels.

So you could in principle have a maximum of 20315 gismu forms and
respect all the current forbidden clusters and blocking rules.

mu'o mi'e xorxes

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