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Date: Wed, 6 Mar 2002 14:32:25 EST
Subject: Re: [lojban] Re: [jboske] Quantifiers, Existential Import
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In a message dated 3/6/2002 12:46:11 PM Central Standard Time, cowan@ccil.org 
writes:


> All S is P (A): SP = S
> Some S is P (I): SP /= 0
> No S is P (E): SP = 0
> Some S is not P (O): SP /= S
> 
> Then existential import is simply the assertion that S /= 0, and we can
> understand I- as asserting that S, which may be null, has a non-null
> intersection with P. But plainly no set P can have a non-null intersection
> with 0, and so from SP /= 0 we can deduce that S /= 0. Therefore I-
> is false if S = 0, and to assert anything useful we need I+.
> 
I- is "SP/=0 OR S=0" on this reading, so, while, when S=0 the SP part drops 
out, when SP/=0 (and hence a fortiori S/=0) then an number (1 or greater) of 
Ss may be Ps. So, I- is compatible with any number (0 or greater) of Ss 
being Ps. To be sure, the useful part is I+, but that can't be derived from 
"not both SP=0 and S/=0". You might expect E+ to be pretty useless, too, but 
it seems quite normal.

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<HTML><FONT FACE=arial,helvetica><BODY BGCOLOR="#ffffff"><FONT style="BACKGROUND-COLOR: #ffffff" SIZE=2>In a message dated 3/6/2002 12:46:11 PM Central Standard Time, cowan@ccil.org writes:<BR>
<BR>
<BR>
<BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px">All S is P (A):&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; SP = S<BR>
Some S is P (I):&nbsp;&nbsp;&nbsp; SP /= 0<BR>
No S is P (E):&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; SP = 0<BR>
Some S is not P (O):&nbsp;&nbsp;&nbsp; SP /= S<BR>
<BR>
Then existential import is simply the assertion that S /= 0, and we can<BR>
understand I- as asserting that S, which may be null, has a non-null<BR>
intersection with P.&nbsp; But plainly no set P can have a non-null intersection<BR>
with 0, and so from SP /= 0 we can deduce that S /= 0.&nbsp; Therefore I-<BR>
is false if S = 0, and to assert anything useful we need I+.<BR>
</BLOCKQUOTE><BR>
I- is "SP/=0 OR S=0"&nbsp; on this reading, so, while, when S=0 the SP part drops out, when SP/=0 (and hence a fortiori S/=0) then an number (1 or greater) of Ss may be Ps.&nbsp; So, I- is compatible with any number (0 or greater) of Ss being Ps.&nbsp; To be sure, the useful part is I+, but that can't be derived from "not both SP=0 and S/=0".&nbsp; You might expect E+ to be pretty useless, too, but it seems quite normal.</FONT></HTML>

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