From jay.kominek@colorado.edu Thu May 02 17:17:33 2002 Return-Path: X-Sender: kominek@ucsub.colorado.edu X-Apparently-To: lojban@yahoogroups.com Received: (EGP: mail-8_0_3_1); 3 May 2002 00:17:33 -0000 Received: (qmail 26973 invoked from network); 3 May 2002 00:17:32 -0000 Received: from unknown (66.218.66.218) by m10.grp.scd.yahoo.com with QMQP; 3 May 2002 00:17:32 -0000 Received: from unknown (HELO ucsub.colorado.edu) (128.138.129.12) by mta3.grp.scd.yahoo.com with SMTP; 3 May 2002 00:17:32 -0000 Received: from ucsub.colorado.edu (kominek@ucsub.colorado.edu [128.138.129.12]) by ucsub.colorado.edu (8.11.6/8.11.2/ITS-5.0/student) with ESMTP id g430HVJ08530 for ; Thu, 2 May 2002 18:17:31 -0600 (MDT) Date: Thu, 2 May 2002 18:17:31 -0600 (MDT) To: lojban@yahoogroups.com Subject: Re: Fw: [lojban] cipja'o In-Reply-To: <004d01c1f1e4$eb58fe00$499eca3e@oemcomputer> Message-ID: MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=utf-8 Content-Transfer-Encoding: QUOTED-PRINTABLE From: Jay Kominek X-Yahoo-Group-Post: member; u=20706630 X-Yahoo-Profile: jfkominek On Thu, 2 May 2002, G. Dyke wrote: > so transcendental numbers are those which cannot solve poynomial equation= s? > > what does that make them?? Nono, they can be the roots of polynomial equations (geez, can't believe I screwed that up in my previous email), but not of polynomial equations with integer coefficients. For instance, if your polynomial has got a transcendental coefficient, then you can (and likely will) have transcendental roots. However, polynomials with integer coefficients can have irrational roots, for instance, x^2-2=3D0, has roots of +sqrt(2) and -sqrt(2), which are both irrational. (Meaning you can't express them as p/q where p and q are integer.) - Jay Kominek Plus =C3=A7a change, plus c'est la m=C3=AAme chose