Subject: Re: [lojban] Quaternions

From: Invent Yourself <[email-masked]>
Date: Fri, 2 Feb 2001 23:45:48 -0500 (EST)

On Fri, 2 Feb 2001, Pierre Abbat wrote:

> I propose the following notation for quaternions:
>
> pa = ka'oxino = 1
> ka'o = ka'oxipa = i
> ka'oxire = j
> ka'oxici = k
>
> Thus voka'omuka'oxiciso = 4+5i+9k.
> But if someone for some other reason wanted to subscript ka'o with a number
> greater than 9, we'd run into trouble. (The most I can imagine subscripting
> ka'o with is 7 for octonions.) Another way to say it would be:
>
> pa = 1
> ka'opa = i
> ka'oka'opa = j
> ka'oka'oka'opa = k
>
> so 4+5i+9k would be voka'omuka'oka'oso.
>
> Comments?

xamgu .i do ka'e pilno zo vei joi zo ve'o le barna sruri be le ka'o namcu
pe zmadu li so

.i ji'a mi stidi le zu'o pilno lo'u xi'i le'u le fanmo be zo xi .i simlu
le ka tu'a zo ke joi zo ke'e

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