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Date: Sat, 4 Aug 2001 18:32:24 EDT
Subject: Re: [lojban] du'u & ka (was: ce'u (was: vliju'a
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In a message dated 8/4/2001 4:14:14 PM Central Daylight Time, 
xod@sixgirls.org writes:


> > I *think* I recall a weak consensus that du'u = ce'u-less ka,
> > which implies that ka must contain an implicit or explicit
> > ce'u.
> 
> 
> 
> 
> I recall Cowan saying something like this too. I would love to hear more
> about this!
> 

Whether Cowan said it or not, it makes a good deal of logical sense. On one 
popular view, a proposition is a function from worlds into truth values. On 
that view, a n-place property is a function from worlds into the set of sets 
of n-tuples in the domains of the worlds. A property defined without a 
{ce'u} is 0-placed and so, in each world it gives the set of 0-tuples that 
satisfies it. Since there is only 1 0-tuple (0), there are only two such 
sets, 0 and {0}. The result is thus isomorphic to a proposition at least. 
Of course, there are other ways of doing things that give quite different 
results.

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<HTML><FONT FACE=arial,helvetica><BODY BGCOLOR="#ffffff"><FONT SIZE=2>In a message dated 8/4/2001 4:14:14 PM Central Daylight Time, 
<BR>xod@sixgirls.org writes:
<BR>
<BR>
<BR><BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px">&gt; I *think* I recall a weak consensus that du'u = ce'u-less ka,
<BR>&gt; which implies that ka must contain an implicit or explicit
<BR>&gt; ce'u.
<BR>
<BR>
<BR>
<BR>
<BR>I recall Cowan saying something like this too. I would love to hear more
<BR>about this!
<BR></BLOCKQUOTE>
<BR>
<BR>Whether Cowan said it or not, it makes a good deal of logical sense. &nbsp;On one 
<BR>popular view, a proposition is a function from worlds into truth values. On 
<BR>that view, a n-place property is a function from worlds into the set of sets 
<BR>of n-tuples in the domains of the worlds. &nbsp;A property defined without a 
<BR>{ce'u} is 0-placed and so, in each world it gives the set of 0-tuples that 
<BR>satisfies it. &nbsp;Since there is only 1 0-tuple (0), there are only two such 
<BR>sets, 0 and {0}. &nbsp;The result is thus isomorphic to a proposition at least. &nbsp;
<BR>Of course, there are other ways of doing things that give quite different 
<BR>results.</FONT></HTML>

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