Re: [bpfk] BAhE + BU

[Daniel Brockman <daniel@brockman.se>]

I believe the short answer is as follows: "When two magic operators are
in conflict, the leftmost operator always wins."

So {zo ba'e bu} is a letteral (because {zo} wins over {ba'e}) and {broda
ba'e bu} is an emphasized letteral (because {ba'e} wins over {bu}).

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