Re: [lojban-beginners] Re: mi do dunda be ti

[Jonathan Jones <eyeonus@gmail.com>]

He is wrong about the interpretation, but he's not wrong about the result. This is the output of {mi do dunda be ti}:

[1(2[dunda1 (give-r(s))
:] mi
I, me)2 (3[dunda3 (recipient(s))
:] do
you)3
[is, does] «4{5dunda
giv-ing be
  (6[dunda2 (gift(s))
:] ti
this here)6}5»4]1

On Tue, Jun 5, 2012 at 5:28 AM, ianek <janek37@gmail.com> wrote:

You're wrong, jbofi'e doesn't interpret {be} that way. Proof: {mi fe
do dunda be ti}. Here, do goes into dunda2, not the x2 of "x1 gives
this to x2".

mu'o mi'e ianek

On 5 Cze, 11:50, tengo <yurock.te...@gmail.com> wrote:
> There are also other ways to confuse people, so your example just adds
> to that number. :) For another example, consider heavy use of FA and
> SE:
>
> fi la .man. la .filadelfias. te se ve klama fa la .ostin.
>
> From a similar discussion at this group I gathered that jbofi'e
> interprets {mi do dunda be ti} is correctly. For those who wonder,
> here is how it works.
>
> {dunda}
> x1 gives x2 to x3
>
> When you attach a sumti to brivla with {be}, it fills one of brivla's
> places and deletes it from numbered place structure of selbri.
>
> {dunda be ti}
> x1 gives this to x2
>
> Then {mi} and {do} fill the x1 and x2 of the resulting selbri.
>
> {mi do dunda be ti} = {mi dunda be ti do}
> I give this to you.
>
> Although, my opinion about this interpretation is not backed by
> official sources. I may need to read more.

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