Pierre Abbat wrote:
I think {ju'u} is in the wrong selma'o. All other binary mex operands take two numbers and return a number. {ju'u} takes a naclerpoi and a number and returns a number.ze bi'esu'i bi pi'i so = (7+8)*9 ze bi'esu'i bi ju'u so = ? is it 14 (which is written 15 in base 9) or what?
It's nonsense. The reason ju'u is an operator rather than a PA is to allow talking about variable bases: (10 base b) - 1 = 10 base (b - 1), e.g. But the left operand can't be anything but a digit string: (a+b) base c is just nonsense. -- Not to perambulate || John Cowan <jcowan@reutershealth.com> the corridors || http://www.reutershealth.com during the hours of repose || http://www.ccil.org/~cowan in the boots of ascension. \\ Sign in Austrian ski-resort hotel