du'u & ka (was: ce'u (was: vliju'a

[Invent Yourself <xod@sixgirls.org>]

On Sat, 4 Aug 2001, And Rosta wrote:

> I *think* I recall a weak consensus that du'u = ce'u-less ka,
> which implies that ka must contain an implicit or explicit
> ce'u.




I recall Cowan saying something like this too. I would love to hear more
about this!




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