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Lojbanistan Hadron Collider (was Re: Lojban is *NOT* broken! Stop saying that! (was Re: [lojban] Re: Vote for the Future Global Language))



On 1/5/11, Remo Dentato <rdentato@gmail.com> wrote:
> I'm not against exploring how much {si} will make the universe collapse in a
> black hole.

Neither am I!

==BEGIN TL;DR==

It would likely take a few {si}'s to erase an event -- events are most
likely in the form of something like {.i xyxi pa darxi xyxi re} (xy.
refers to all particles, so xy.xiny. refers to the nth particle). In
this case, the number of words it takes to refer to a particular
particle depends on the total number of particles in the universe.
Specifically, the formula is 2 + (interacting particles)*(particle
reference word count)

(Also possible is that, instead of using an index for all particles,
there is a description, perhaps something like {le kantu be la xunre
je cizra}. In this case, 7 words. There also might be something like
the coordinates on the grid on WP:Standard_Model . In which case, we'd
get {le kantu be li pa .e li re}, for 8. As a final of many
possibilities, I offer that each particle type has a name, in which
case 2 words. (Tho this brings up the "Toyata" problem; I do not
recall what the answer for that is.))

Returning to the question of how many words it takes to refer to an
index particle, let N be the number of atoms in the universe, which
is, per WolframAlpha, 10^80 . WP:Chemical_Abundance tells me that the
universe is about 3/4 hydrogen 1/4 helium. So, H = (3/4)N protons +
(3/4)N electrons, and He = 2*(1/4)N protons + 2*(1/4)N neutrons +
2*(1/4)N electrons. WP:Proton, WP:Neutron, an WP:Standard_Model
suggest to me that protons and neutrons each have 3 elementary
particles, and an electron is 1 elementary particle. So, U = [(3/4)N*3
+ (3/4)N*1] + [2*(1/4)N*3 + 2*(1/4)N*3 + 2*(1/4)N*1]. Zapping the Wand
of Maximas, we conclude that there are P = 6.5*10^80 particles in the
universe (the same order of magnitude as N).

(This result is obviously wrong; I've neglected the photons, the rest
of the elements, your mom, whether N includes other forms of matter,
etc. Also, I fails at maths. Likely there is someone who actually
knows what ri is doing, and has a provided a better answer on the
Internet. This potential resource was carefully ignored for the lolz.)

The particle index could potentially be written in other bases. Base 2
would take too long, base 5 is my pet fave, so of course would not be
used. Dozenal is a number system for devil satan heathens, so God
wouldn't use it. Lojban lacks convenient support for base 60, so is
also unlikely to be used. Recursive calls to a successor function
might be used, but that would be even worst than base 2. The best
offense for what I'm pushing for is base 16. As we were made in His
image, or something, the bases used are either 10, or 20. But, 20
suffers from the same problems as 60; no words for the numbers. So,
particles would be indexed in base 10. Therefore, an index requires up
to 81 words to speak of any arbitrary particle. Adding the "xyxi", we
need 83 words to refer to a particle.

Each event would involve 2 particles. (There may occasionally be
events involving less.) Let us suppose that each particle interacts
with 8 of its nearest neighbors each time step t_p = 10^-44s
(WP:Planck_time). WP:Age_of_the_universe gives us 4.3*10^17 seconds as
the age of the universe, so the universe is 4.3*10^61 ticks old. Then,
(8 events/particle * P particles) = 8P events/tick = 8*P*4.3*10^61
events = 2.2*10^143 events have occurred Since The Beginning Of Time
Itself. (Wrong because I don't know how many events per particle per
second actually happen.)

(total number of events) * (words in each event) =
(2.2*10^143)*(2+3*(83)) = 5.5*10^145

==END TL;DR==
(If you didn't read all of that, I will eat your flesh.)

Therefore, it takes 5.5*10^145 {si}'s to return to the beginning of
the universe. ∎

Honestly, it'd be much easier to just use {su}. God is quite qualified
to speak on the subject: http://jbotcan.org/jbo/arch/res/1093.html


mu'omi'e.djeims.

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