Re: [bpfk] BAhE + BU

[Jorge Llambías <jjllambias@gmail.com>]

On Tue, Jun 10, 2014 at 12:29 PM, John Cowan <cowan@mercury.ccil.org> wrote:

Daniel Brockman scripsit:

> I believe the short answer is as follows: "When two magic operators are
> in conflict, the leftmost operator always wins."

There's nothing magic about "ba'e", though; it's a regular part of the grammar.
That means it loses to any magic word, just like all other non-magic words.

I don't know if we have an explicit statement anywhere about what makes magic words magic, but I would say it's these two properties:

(1) It can modify (almost) any other word.

(2) The grammar of the resulting construct is independent of the class of the word(s) it modifies.

The "almost" is of course necessary because of the interactions between magic words. They can certainly modify any non-magic word.

UI and BAhE satisfy condition (1) for the most part, they are not very choosy in what they interact with, but not condition (2), because the resulting constructs retain the grammar of the word they modify.

mu'o mi'e xorxes

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