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Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
Aren't any unbound 'da's, each is inherently bound by a particular quantifier. That is a difference fro 'ko'a', which refers to specific referential.
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On Aug 16, 2011, at 9:21, tijlan <jbotijlan@gmail.com> wrote:
> Suppose there is a context where I have not specified "da" and "ko'a".
> Under what additional condition should I have "da poi ..." and not
> "ko'a poi ..." in order to create a re-usable variable for a specific
> referent? What is it that "da" can achieve but "ko'a" cannot, besides
> that unbound "da" is meaningless?
>
> mu'o
>
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- References:
- [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: tijlan <jbotijlan@gmail.com>
- Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: Jonathan Jones <eyeonus@gmail.com>
- Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: Robin Lee Powell <rlpowell@digitalkingdom.org>
- Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: Jonathan Jones <eyeonus@gmail.com>
- Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: Robin Lee Powell <rlpowell@digitalkingdom.org>
- Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: Jonathan Jones <eyeonus@gmail.com>
- Re: [lojban] da broda, ko'a broda, da bu'a, zo'e co'e
- From: tijlan <jbotijlan@gmail.com>